Question

The diameter of a lead ball is 2.1cm the density of the lead used is 11.34g/c3 what is the weight of the ball.

Answer 1

$\mathfrak{Heya\: mate. \: Solution \: below.}$
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★ SPHERES ★ 

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$<font color = "red"><u>Answer - </u></font color>$


• Given Diameter of lead ball (probably spherical) = 2.1 cm


=>> Radius of the ball,

= d/2

= 2.1/2

= 1.05 cm



• Then, Volume of the sphere,

= $\frac{4}{3} \pi {r}^{2}$

= $\frac{4}{3} \times \frac{22}{7} \times 1.05 \times 1.05 \times 1.05$

= $\frac{101.871}{21}$

= 4.851 cm³



• Now, we know that,

$density \: = \: \frac{mass }{volume}density=volumemass​$

$= > \: mass \: = \: density \: \times \: volume$



• Then, mass of the lead ball,

= $v \: \times \: d$

= $4.851 \times 11.34$

= 55.01034 g

≈ 55 g



•°• The lead ball weighs 55 g (approximately)
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Thank you... (^_-)

Answer 2

Answer:

Step-by-step explanation:

This is simple.

GIVEN THAT DIAMETER OF LEAD BALL(d) ::: 2.1 cm

Radius(r)::: 2.1/2::: 1.05 cm

Density is 11.34 g/cm^3

Volume of sphere ::: 4/3πr^3

=4/3 × 22/7× 1.05×

1.05× 1.05

=88×1.157625/27

=101.871/27

=4.851 cm^3 .

Weight of lead ball= 4.851×11.34

=55.01

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