The diameter of a lead ball is 21 cm. The density of the lead used is 11.34 g/c^3 What is the weight of the ball ?
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ANSWER :-
WE KNOW THAT:
- DENSITY = MASS / VOLUME
- MASS = VOLUME × DENSITY
WE KNOW THAT VOLUME OF SPHERE = 4/3 πR^3
GIVEN:
DIAMETER OF THE LEAD BALL = 21 Centimetres
Therefore Radius of the sphere will be 10.5 Centimetres
By substituting the radius value in the volume of sphere formula we get:
==> 4/3 × 3.14 × (10.5)^3
==> 4,846.59 cm^3
- We know that Mass = Volume × Density
BY SUBSTITUTING THE VALUES WE OBTAINED WE GET:
MASS = 4,846.59 × 11.34
= 55,202.66 grams
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