The diameter of a lead ball is2.1cm.the density of the lead used is 11.34g/c.what is the weight of the ball
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Answered by
11
Diameter of a ball = 2.1 cm
Radius = 2.1/2 = 1.05 cm
Density = 11.34 g/c
Volume = 4/3 πr^3
= (4/3)×(22/7)×(1.05)^3
= 4×22×1.157625/7
= 88×0.165375
= 14.553 cm^3
Density = Mass/Volume
11.34 = mass/14.553
_______________
Mass = 165.03 g
Radius = 2.1/2 = 1.05 cm
Density = 11.34 g/c
Volume = 4/3 πr^3
= (4/3)×(22/7)×(1.05)^3
= 4×22×1.157625/7
= 88×0.165375
= 14.553 cm^3
Density = Mass/Volume
11.34 = mass/14.553
_______________
Mass = 165.03 g
Sagittarius29:
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Answered by
12
Here, Diameter of ball=2.1 cm
So, radius=2.1/2=10.5 cm.
Now, volume of spherical ball= 4/3 π r^3
= 4/3×22/7×10.5×10.5×10.5
=4851 cm^3.
We know that, Density=Mass/Volume
So, Mass(weight)= Density×volume
11.34g/cm^3× 4851cm^3
=55010.34 g.
It is your required answer.
So, radius=2.1/2=10.5 cm.
Now, volume of spherical ball= 4/3 π r^3
= 4/3×22/7×10.5×10.5×10.5
=4851 cm^3.
We know that, Density=Mass/Volume
So, Mass(weight)= Density×volume
11.34g/cm^3× 4851cm^3
=55010.34 g.
It is your required answer.
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