Math, asked by seemagupta2753, 4 months ago

the diameter of a metallic ball is 8.4 cm what is the mass of the ball if the density of the metal is 8.9 g per cm^3​

Answers

Answered by prabhas24480
1

Step-by-step explanation:

Given,

diameter of the metallic ball =4.2 m

We know,

radius =

2

diameter

∴ r=

2

4.2

cm=2.1 cm

Density =

volume

Mass

∴ Mass = Density×volume

⇒ 8.99 cm

2

×volume

volume of a metallic ball =

3

4

×π×r

3

=

3

4

×2.1×2.1×2.1 cm

3

∴ Mass=8.99×

3

4

×π2.1×2.1×2.1 cm

3

=345.077 gm

Answered by sneharana0406
1

2791.07136gm

Step-by-step explanation:

diameter of metallic ball=8.4cm

radius=d/2

=8.4/2

=4.2

density=mass/volume

mass=density×volume

=8.99cm³×volume

volume of metallic ball=4/3×22/7×r³

4/3×22/7×4.2×4.2×4.2

mass=8.99×4/3×22/7×4.2×4.2×4.2

=2791.07136gm

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