the diameter of a metallic ball is 8.4 cm what is the mass of the ball if the density of the metal is 8.9 g per cm^3
Answers
Answered by
1
Step-by-step explanation:
Given,
diameter of the metallic ball =4.2 m
We know,
radius =
2
diameter
∴ r=
2
4.2
cm=2.1 cm
Density =
volume
Mass
∴ Mass = Density×volume
⇒ 8.99 cm
2
×volume
volume of a metallic ball =
3
4
×π×r
3
=
3
4
×2.1×2.1×2.1 cm
3
∴ Mass=8.99×
3
4
×π2.1×2.1×2.1 cm
3
=345.077 gm
Answered by
1
2791.07136gm
Step-by-step explanation:
diameter of metallic ball=8.4cm
radius=d/2
=8.4/2
=4.2
density=mass/volume
mass=density×volume
=8.99cm³×volume
volume of metallic ball=4/3×22/7×r³
4/3×22/7×4.2×4.2×4.2
mass=8.99×4/3×22/7×4.2×4.2×4.2
=2791.07136gm
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