Math, asked by sanjaysmart574, 1 year ago

The diameter of a metallic sphere is 6 CM it is melted and drawn into a wire having diameter of the cross section of 0.2 cm find the length of the wire

Answers

Answered by jarpana2003
0

Answer:

Step-by-step explanation:

volume of sphere=volume of cylinder

\frac{4}{3} \times \pi \times  {r}^{3}  = \pi \times  {r}^{2}  \times h

4/3×6×6×6=.3×.3×h

h=8×6×6/.3×.3

h=3200cm or 32m


sanjaysmart574: Wrong
sanjaysmart574: H36m
Answered by shivam6112002
1
it is solved by using the concept of equal volume.

vol. of sphere= vol. of cylindrical wire

(4πR³)/3 = πr²h (h= length of the wire)

4R³/3 = r²h

( 4R³)/(3r²) = h

(4*6*6*6)/(3*0.1*0.1)= h

h= 28800 cm

h= 28.8m

hence required length of wire is equal to 28.8 m
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