The diameter of a metallic sphere is 6 CM it is melted and drawn into a wire having diameter of the cross section of 0.2 cm find the length of the wire
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Answer:
Step-by-step explanation:
volume of sphere=volume of cylinder
\frac{4}{3} \times \pi \times {r}^{3} = \pi \times {r}^{2} \times h
4/3×6×6×6=.3×.3×h
h=8×6×6/.3×.3
h=3200cm or 32m
sanjaysmart574:
Wrong
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it is solved by using the concept of equal volume.
vol. of sphere= vol. of cylindrical wire
(4πR³)/3 = πr²h (h= length of the wire)
4R³/3 = r²h
( 4R³)/(3r²) = h
(4*6*6*6)/(3*0.1*0.1)= h
h= 28800 cm
h= 28.8m
hence required length of wire is equal to 28.8 m
vol. of sphere= vol. of cylindrical wire
(4πR³)/3 = πr²h (h= length of the wire)
4R³/3 = r²h
( 4R³)/(3r²) = h
(4*6*6*6)/(3*0.1*0.1)= h
h= 28800 cm
h= 28.8m
hence required length of wire is equal to 28.8 m
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