the diameter of a raller 120cm long is 84cm if it takes 500 complete revolutions to level a playground determine the cost of leveliing it at the rate of 30 haise per square metre
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Answered by
1
Answer:
Clearly the roller is a right circular cylinder of height h=120 cm
and radius of its base =r=42 cm
∴ area covered by the roller in one revolution = curved surface area of the roller
=2×
7
22
×42×120cm
2
=31680cm
2
so, area covered by the roller is 500 revolution = (31680×500)cm
2
=
100×100
31680×500
m
2
=1584m
2
hence , cost of levelling the playground = 1584×
100
30
=Rs475.20
Answered by
0
real answer is
is
is
is
is
Rs475.20
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