Math, asked by mohindersingh63104, 6 days ago

the diameter of a raller 120cm long is 84cm if it takes 500 complete revolutions to level a playground determine the cost of leveliing it at the rate of 30 haise per square metre​

Answers

Answered by AnkeetSwarnakarYT
1

Answer:

Clearly the roller is a right circular cylinder of height h=120 cm

and radius of its base =r=42 cm

∴ area covered by the roller in one revolution = curved surface area of the roller

=2×

7

22

×42×120cm

2

=31680cm

2

so, area covered by the roller is 500 revolution = (31680×500)cm

2

=

100×100

31680×500

m

2

=1584m

2

hence , cost of levelling the playground = 1584×

100

30

=Rs475.20

Answered by dakshdhakadhaka
0

real answer is

is

is

is

is

Rs475.20

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