Question

The diameter of a right circular cone is 8 cm and its volume is 48 cm3. What is its height ?​

Answer 1

Answer:

Let h be the height of the cone.

Diameter = 8 cm

Radius = 4 cm

Volume = 48π cm

3

3

1

π×(4)

2

×h=48π

h=9 cm

Hence, the height of the cone is 9 cm.

Answer 2

Correct Question:-

• The diameter of a right circular cone is 8 cm and its volume is 48 π cm3. What is its height ?

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Given:-

• Diameter of a right circular cone is 8 cm.
• Volume of a right circular cone is 48 π cm³.

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To find:-

• Height of the cone.

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Solution:-

Let,

• the height of the cone be h.

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Formula used:-

${\dag}\:{\underline{\boxed{\sf{\purple{Volume_{(cone)} = \dfrac{1}{3}\pi rh}}}}}$

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$\tt\longrightarrow{\dfrac{1}{3}\pi \times 4^2 \times h = 48\pi}$

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$\tt\longrightarrow{5.3\times h = 48}$

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$\tt\longrightarrow{h = \dfrac{48}{5.3}}$

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$\tt\longrightarrow{\boxed{\orange{h = 9\: cm}}}$

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Hence,

• the height of the right circular cone is 9 cm.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$