Question

the diameter of a right circular conical tent is 6m. if a pele of length 2m can be fixed up in the tent at half the distance of radius from the centre of the base, then find the area of the canvas required to make the tent

Answer 1

Answer:

Step-by-step explanation:

circumference of base of tent = 44m we know, circumference of circle = 2πr 44m = 2 × 22/7 × r r = 7m hence, radius of base of tent , r = 7mheight of conical tent, h = 10mso, slant height of conical tent , l = √(h² + r²) = √{10² + 7²} = √{100 + 49} = 12.2 m now, surface area of tent = area of rectangular canvas πrl = L × B22/7 × 7 × 12.2 = L × 2m22 × 6.1 = L hence, L = 134.2 m hence, length of canvas used in making the tent is 134.2m

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Answer 2

Answer:

circumference of base of tent = 44m we know, circumference of circle = 2πr 44m = 2 × 22/7 × r r = 7m hence, radius of base of tent , r = 7mheight of conical tent, h = 10mso, slant height of conical tent , l = √(h² + r²) = √{10² + 7²} = √{100 + 49} = 12.2 m now, surface area of tent = area of rectangular canvas πrl = L × B22/7 × 7 × 12.2 = L × 2m22 × 6.1 = L hence, L = 134.2 m hence, length of canvas used in making the tent is 134.2m