Question

The diameter of a road roller 120cm long is 84cm. If it takes 500 complete revolutions to level the playground, determine the cost of
leveling it at the rate of 30 paise per sq metre.​

Answer 1

$answer$

2r = 84cm

∴ r = 84/2cm = 42cm h

= 120cm

Area of the playground leveled in one complete

revolution = 2πrh = 2 × 22/7 × 42 × 120 × 31680cm²

∴ Area of the playground = 31680 × 500cm²= (31680 x 500)/(100 x 100)m² = 1584m²

cost of leveling=Rs475.20

Answer 2

Step-by-step explanation:

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