Question

The diameter of a road roller, 120cm long is 84cm. If it takes 500 complete revolution to level a playground find the cost of leveling it at the rate of Rs 2 per square meter​

Answer 1

rs . 31680000

Step-by-step explanation:

Diameter of road roller = 120 cm

radius of road roller = 120/2 = 60 cm

length ( height ) of road roller = 84 cm

Lateral surface area of the road roller = 2πrh

= 2×22/7×60×84( cut 84 with 7 = 12)

= 2×22×60×12

= 44×720

=31680 cm²

Area of playground = 500× LSA of road roller

= 500×31680 = 15840000m²

cost of leveling per m² = Rs. 2

cost of leveling 15840000 m² = 2× 15840000

= rs . 31680000