The diameter of a road roller, 1m40cm long is 80cm. If it takes 600 revolutions to level a
playground, find the cost of leveling the ground at * 3 per sq m.
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Step-by-step explanation:
and it takes 600 revolutions to level a playground. consider the roller as a cylinder. C.S.A 2πrh = 2 x 3.14 x 0.4 x 1.4 =3.5168 square meter. It is given that,the cost of leveling the ground at Rs 15 per square meter.
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