The diameter of a road roller is 1.5 m and length is 84cm.if it takes 40 complete revolution to level road ground,find the cost of levelling the road at the rate of ₹1.60per sq.m
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Step-by-step explanation:
Here , d = 2r = 1.5 m = 150 cm and l = h = 84 cm is given.
and n = 40 revolution
Total area = n × pi × d × h
= 40 × 22/7 × 150 × 84
= 1584000 cm^2
= 158.4 m^2
The cost of levelling = 158.4 × 1.6
= 253.44 ₹
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