Math, asked by ahemraza777, 1 day ago

The diameter of a road roller is 1.5 m and length is 84cm.if it takes 40 complete revolution to level road ground,find the cost of levelling the road at the rate of ₹1.60per sq.m​

Answers

Answered by gopaninemil13
0

Step-by-step explanation:

Here , d = 2r = 1.5 m = 150 cm and l = h = 84 cm is given.

and n = 40 revolution

Total area = n × pi × d × h

= 40 × 22/7 × 150 × 84

= 1584000 cm^2

= 158.4 m^2

The cost of levelling = 158.4 × 1.6

= 253.44 ₹

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