Question

the diameter of a road roller is 1 m40 cm long is 70 cm find Find the number of revolution
to level the road if the total cost of levelling the road at r₹7 m^2 is rupees 17248. ​

Answer 1

Answer:

Jio

Step-by-step explanation:

you can get answers in ..............

Answer 2

Answer:

Number of revolutions = 8

Step-by-step explanation:

Diameter = 140 cm

=> radius = 70 cm

also, length = 70 cm (given)

CSA (cylinder) = $2\pi rh$ = 2 x 22/7 x 70 x 70  = 30800 $cm^{2}$ = 308 $m^{2}$

also, area = total cost / cost per meter

   => total area = 17248/7 = 2464 m.

Therefore,

no. of revolutions = total area / area in one revolution

                             = 2464 / 308 = 8

Thus, 8 revolutions

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