The diameter of a road roller is 140cm and its length is 2.2m. It takes 400 complete revolutions to move once over to level a stretch of road 2.2m wide. Find the surface area of the stretch of road leveled in m2. (Take = 22) 7
Answers
Answered by
19
heya dear!!
Diameter of a road roller =140cm=1.4m
Radius = 1.4/2=0.7m
Length =2.2 m
no. of revolutions =400
Area covered by the roller in 1 revolution=CSA of roller=2Πrh
Now,
Area covered by the roller in 400 revolutions=400×9.68=3872
which is the surface area of stretch of a road levelled.
HOPE IT HELPS YOU ..
PLEASE MARK ME BRAINLIEST
Diameter of a road roller =140cm=1.4m
Radius = 1.4/2=0.7m
Length =2.2 m
no. of revolutions =400
Area covered by the roller in 1 revolution=CSA of roller=2Πrh
Now,
Area covered by the roller in 400 revolutions=400×9.68=3872
which is the surface area of stretch of a road levelled.
HOPE IT HELPS YOU ..
PLEASE MARK ME BRAINLIEST
Answered by
3
Answer:
Diameter of a road roller =140cm=1.4m
Radius = 1.4/2=0.7m
Length =2.2 m
no. of revolutions =400
Area covered by the roller in 1 revolution=CSA of roller=2Πrh
Now,
Area covered by the roller in 400 revolutions=400×9.68=3872
which is the surface area of stretch of a road levelled.
Step-by-step explanation:
Similar questions