Question

the diameter of a road roller is 18 cm and it is 2.8cm long. How much area will it cover in 25 revolutions in levelling a road

Answer 1

Step-by-step explanation:

so first we have to find the lateral surface area of road roller

lateral surface area of road roller = 2πrh

here diameter is given so we have to divide it with 2 to find radius SO

= 18/2

= 9 it's the radius

now put the value

= 2 × 22/7 × 9 × 2.8

= 158.4 square cm

now how much area covered in 25 revolution

= 158.4 × 25

= 3960 square cm