Question

the diameter of a road roller is 28 cm and its length is 150 cm It takes 500 Revolution to level a piece of land find the area of the land the cost of levelling the ground is 100 per square metre find the cost of levelling the ground

Answer 1

Hey!! Here is your answer!!
Diameter=28cm
Radius=28/2 =14cm
Length of cylinder =150cm

C.S.A. Of cylinder=2x pi x r x h
=2 X 22/7 X 14 X 150
13200cm sq.

Area covered in 1 revolution=13200cm sq.
Area covered in 500 revolutions=13200X500
=6600000cm sq.
Cost of levelling a ground=Rs 100 per m sq.
Cost of levelling a 660 m sq ground =660X100=Rs 66000m sq

Since 1 m sq = 10000cm sq
6600000cm sq= 660m sq

ANS=Rs 66000m sq.

Answer 2

Step-by-step explanation:

diameter of road roller

length=150cm

radius=28/2=14cm

14/100=0.14m

height=150/100=1=5m

Area of curved surface =2πrh

2*22/7*0.14m*1.5m=1.32m^2

Area of ground =500*1.32m^2=660m^2

cost of levelling per m^2=₹100

cost of levelling660m^2=₹100*660

=₹66000