The diameter of a road roller is 84 cm and its length is 1m how many revolution will it make to level a playground in 1989 sq m in area
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r=84/2=42cm
ar. of roller=C.S.A
=2pie rh
=2*22/7*42*100
=26400 sq cm
ar of 1 revolution=26400=26400/10000
=2.64 sq n
ar of 1989 revolution=2.64*1989=5250.96sq m
ar. of roller=C.S.A
=2pie rh
=2*22/7*42*100
=26400 sq cm
ar of 1 revolution=26400=26400/10000
=2.64 sq n
ar of 1989 revolution=2.64*1989=5250.96sq m
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