the diameter of a road roller is 98 cm and its 1 meter long .find the number of complete revolutions it should take to move once over to level a road which is 539 m long and 4m wide
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sorry I don't know please forgive me
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same model but different numbers.... same sum...apply those numbers and do it u will get the answer 1400m*2... It can be observed that a roller is cylindrical.
Height (h) of cylindrical roller = Length of roller = 120 cm
Radius (r) of the circular end of roller =
CSA of roller = 2πrh

Area of field = 500 × CSA of roller
= (500 × 31680) cm2
= 15840000 cm2
= 1584 m2
Height (h) of cylindrical roller = Length of roller = 120 cm
Radius (r) of the circular end of roller =
CSA of roller = 2πrh

Area of field = 500 × CSA of roller
= (500 × 31680) cm2
= 15840000 cm2
= 1584 m2
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