the diameter of a rollar is 84 cm and its length is 120 cm . it takes 500 complete revolution to move once over to level a playground.find the area of the playground in m square.
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Answered by
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2×22/7×42×120=31680m in one revolution. so area of ground is 500×31680=158400m
Answered by
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Heya !!!
Diameter of rollar = 84 cm
Radius = D/2 = 84/2 = 42 cm
Length of rollar = 120 cm
Curved surface area of rollar = 2πRH
=> 2 × 22/7 × 42 × 120
=> ( 44 × 6 × 120 ) cm²
=> 31680 cm²
Distance moved by rollar in 1 revolution = It's CSA = 31680 cm².
Area of the playground = ( 500 × 31680 ) cm² = 15840000 cm²
Or In metres = 15840000/100 = 158400 m².
★ HOPE IT WILL HELP YOU ★
Diameter of rollar = 84 cm
Radius = D/2 = 84/2 = 42 cm
Length of rollar = 120 cm
Curved surface area of rollar = 2πRH
=> 2 × 22/7 × 42 × 120
=> ( 44 × 6 × 120 ) cm²
=> 31680 cm²
Distance moved by rollar in 1 revolution = It's CSA = 31680 cm².
Area of the playground = ( 500 × 31680 ) cm² = 15840000 cm²
Or In metres = 15840000/100 = 158400 m².
★ HOPE IT WILL HELP YOU ★
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