Math, asked by vaibhavchoudhary0001, 28 days ago

the diameter of a roller 100cm long is 63 cm . if it takes 400 complete revolution tolevel a playground then determine the cost of leveling the playgroud in 30 paise per m sq . pls don't fake out answers and pls tell the explanation​

Answers

Answered by anushkabhatnagar10
2

Answer:

here's ur answer mate..hope it's helpful :))

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Answered by priyadarshinibhowal2
0

The total cost is 23760 paise.

  • The border or entire arc length of a circle's perimeter is known as its perimeter. A circle's circumference is the term used to describe its edge. Therefore, since the perimeter of a circle provides information on its circumference, the formula is also referred to as the circumference of a circle.
  • The radius of the circle serves as one of the three variables in the perimeter of a circle formula, along with two constants.

Here, according to the given information, we are given that,

The diameter of a roller 100cm long is 63 cm.

Now, circumference of the roller is given by, \pi d, where d is the diameter of the given roller.

Then, circumference of the roller = \pi d = \pi (63) = 197.92 cm.

Now, when the roller revolves once, it covers a total area of (\pi d).100 = (197.92).100 = 19792 cm^{2}

Now, 19792 cm² = \frac{19792}{10000} = 1.98m^{2}

Then, for 400 revolutions, we get, area = (1.98)400 = 792m^{2}.

1 m sq. costs Rs. 30 paise.

Then, 792 m sq. will cost, (30.792) = 23760 paise.

Hence, the total cost is 23760 paise.

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