The diameter of a roller, 110 cm long is 84 cm. If it takes 300 complete revolutions to level a playground, find the cost of leveling it at 75 p per sq. m.
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Answer:
diameter=84cm
therefore radius=42cm
height=120cm
area rolled in 1 revolution=c.s.a
=2*22/7*r*h=2*22/7*42*120
316800 cm^2 = 3.168 m^2
area of field=500*3.168
=1584 m^2
cost=30 p/m^2
therefore, total cost=1584*30
47520 p/m^2
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