the diameter of a roller 120 cm long is 84 CM if it takes 500 complete Revolution to level a playground determine the cost of levelling at rupees 25 per metre square
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Answer:
Rs. 23100
Step-by-step explanation:
Number Revolutions = Area of ground/Curved surface area of the roller
500 = x/π*d*h
where, 500 = revolutions
x = area of ground
h = height = 120 cm = 1.2 m
d = 84 cm = diameter = 0.84 m
π = 22/7 = value of pi
∴ x = π*h*d*500 = 22/7×1.2×0.84×500
= 60×15.4 = 924 m²
∵ Area of the ground = 924 m²
Cost per m² = Rs. 25
Total cost = 25×924 = Rs. 23100
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