the diameter of a roller 120 cm long is 84 cm. if it takes 1000complete revolutions to level a a playground what is the area of play ground
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area covered by roller in one revolution = curved surface area of cylindrical roller
curved surface area of cylindrical roller = 2πrh
[ in our case r = 84/2 = 42 cm and h = 120 cm ]
curved surface area of cylindrical roller = 2 × 22/7×42×120 = 31680 cm²
area of play ground = area covered in 1000 revolution = 31680 × 1000
= 31680000 cm²
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