Question

the diameter of a roller 120 cm long is 84 cm. if it takes 500 complete revolutions to level a a playground determine the cost of levelling it at the rate of ₹ 25
per sq metre

Answer 1

Answer:

Step-by-step explanation:

Curved surface area=2πrh*30paise*500 revolutions

Convert r=42cm in m=0.42m and height =1.20 m

Then solve by the above mentioned formula

Answer will be47520paise

To convert in rps divide

By 47250/100=475.20 rps

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