Math, asked by AamirGeneral6015, 1 year ago

The diameter of a roller ,120 cm long is 84 cm .If it takes 500 complete revolution to level a play ground ,find the cost of leveling it at 75 paisa per m2

Answers

Answered by rajasekarvenkatesan
5

Answer:


Step-by-step explanation:

h = 120cm, r = 42cm

area covered in 500 revolution = 500 x 2 x 22 x 120 x 42/7

                                                      = 1000 x 22 x 720

                                                      = 1000 x 15840

                                                      = 1,58,40,000cm^2

                                                      = 1584m^2

Total cost of levelling = 75 x 1584

                                    = 1,18,800 paisa

                                    = Rs1,188

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