the diameter of a roller , 120cm long is 84cm. it takes 500 complete revolution to level a playground . find the cost of levelling it at the rate 25ruppes per sq m
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circumference of roller =2 pir r^2h
=2*22/7 *84*84*120
=44*12*84*120
=5322240 cm^2 =53222.40 m^2
Cost of levelling=53222.40*500
=RS. 26611200. I THINK IT IS CORRECT..! PLEASE COMMENT..
=2*22/7 *84*84*120
=44*12*84*120
=5322240 cm^2 =53222.40 m^2
Cost of levelling=53222.40*500
=RS. 26611200. I THINK IT IS CORRECT..! PLEASE COMMENT..
vishnu84:
answer is wrong
AM SORRY. MY ANSWER IS IN CENTIMETER. IM AM EDIT MY ANSWER PLEASE SEE AGAIN...
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