the diameter of a roller, 120cmlong is 84cm. if it takes 500 complete revolution to a level a playground, find the cost of leveling it at 75 paise per square meter?
hitug123:
plz give me ans of this ques
Answers
Answered by
1
radius of the roller = 42cm
length of the roller = 120cm
so curved surface area of roller = 2 pi r h
= 2 {22 / 7} * 42 * 120 = 31680
then area covered by the roller in 500 revolution = ( 500 * 31680 ) cm ^2
= 15840000 cm ^2 = 1584 m^2
length of the roller = 120cm
so curved surface area of roller = 2 pi r h
= 2 {22 / 7} * 42 * 120 = 31680
then area covered by the roller in 500 revolution = ( 500 * 31680 ) cm ^2
= 15840000 cm ^2 = 1584 m^2
thxx fpr ans
for*
i do not understand
Similar questions