Question

the diameter of a roller 1m long is 42 cm if it takes 300 revolutions to level a playground cost is 1.20 per sq.m.

Answer 1

Answer:

= RS.25.14

Step-by-step explanation:

Area of ground = 400 × CSA of cylindrical roller

= 2 × pi× r×h ×400

= 2×22/7 × 21 × 100 × 400

=5280000 cm^2

=5280000/10000 m^2

= 528 m^2

Cost of levelling 105 m^2 = rs.50

so cost of leveling 1 m^2 = 50/105

So cost of leveling 528 m^2 = 50/105 × 528 = RS.25.14