Question

The diameter of a roller 2.0m long is 100cm. If it takes 100 revolutions
to level a playground, find the cost ifthe rate is Rs.80 per square metre.​

Answer 1

Answer:

Cost of leveling the playground = Rs. 50265.6

Step-by-step explanation:

Given:

Length of roller, L = 2 m

Diameter of roller, d = 100 cm = 1 m

• We know that curved surface area (CSA) of a cylinder is given as:
• CSA = 2*π*r*L
• Where 'r' is the radius of the cylinder and 'L' is the length of the cylinder.
• CSA can also be written as:
• CSA = π*d*L (since 2*r = d)
• Therefore in our case, CSA of the roller can be found out as follows:
• CSA = 3.1416 * 1 * 2 = 6.2832 sq. m
• Now, the roller takes 100 revolutions to level the playground, therefore, the total area covered by the roller is given by:
• Total Area = 6.2832 * 100 = 628.32 sq. m
• The cost of leveling per sq. m is given as Rs. 80 per sq. m, thus, the total cost of leveling the playground is given as follows:
• Total Cost = Total Area * 80 = 628.32 * 80 = Rs. 50265.6
• Hence, the required cost is found to be Rs. 50265.6