Question

the diameter of a roller is 1.4 and its is 2cm long .the it will cover in 5 olution heightarea is65sq ​

Answer 1

Answer:

Diameter = 1.4 m

r = d/2

r = 1.4/2

r = 0.7 m

curved surface area of cylinder =2

∗

22/7

∗

r∧2

=2

∗

22/7

∗

0.7

∗

0.7

=8.8m

∧

2

No of revolution = 5

Therefore =8.8

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∗

5

= 44 m2

Answer 2

Radius of a garden roller (r) = 1.4 / 2 = 0.7 m

and length of the garden roller (h) = 2 m

∴ Curved surface area of garden roller = 2πrh .

So, the area levelled of a garden roller in one revolution is 8.8 m2.

Now, area levelled of a garden in 5 revolutions = 8.8 x 5= 44m2

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