The diameter of a roller is 42 cm and its length is 100 cm . It takes 400 complete Revolutions moving once over to level a playground . Determine the area of the playground
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roller is in a form of cylinder
radius=d/2
r=21 cm
area of roller =curved surface of cylinder
2×pi×r×h
2×3.14×21×100
=13188sqcm
area of 1 revolution=ar.of roller
ar.of 400 revolutions=400×13188= 5275200 sq cm
area of playground=5275200sqcm.
radius=d/2
r=21 cm
area of roller =curved surface of cylinder
2×pi×r×h
2×3.14×21×100
=13188sqcm
area of 1 revolution=ar.of roller
ar.of 400 revolutions=400×13188= 5275200 sq cm
area of playground=5275200sqcm.
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