Question

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolution to move once over to level playground. Find the area of the playground in m^2 .
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Answer 1

Hyy Dude

Given,Diameter = d = 84cmRadius = r = d/2 = 42cmLength = l = 120 cmT.S.A of cylinder = 2πrh                           = 2 x 22/7 x 42 x 120                           = 31680 cm²Area levelled by 500 revolution = Area of playground= 500 x 31680cm²= 15840000 cm² [ change into m]= 1584 m²

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Answer 2

Radius of the roller (r) = 84/ 2 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the roller = 2πrh = 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2 ∴ area covered by the roller in 1 revolution = 31680 cm2 ∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2