Math, asked by Rebel26008, 3 months ago

The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete
revolutions to move once over to level a playground. Find the area of the
playground in m2
.

Answers

Answered by Rohanparida5
2

Radius of the roller (r)= 84\2cm=42

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

length of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm

playground=31680×500=15840000cm 2

=1584m^2

Answered by pritirai1787
7

Answer:

Radius of the roller (r)=

84/2 cm=42cm

cm=42cmlength of the roller (h)=120cm

cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh

cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm

cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2

cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2

cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2 ∴ Area of the playground

=31680×500=15840000cm ^2

15840000/ 100*100m^2

=1584m ^2

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