The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete
revolutions to move once over to level a playground. Find the area of the
playground in m2
.
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Answered by
2
Radius of the roller (r)= 84\2cm=42
length of the roller (h)=120cm
∴ Area of the playground levelled in taking 1 complete revolution 2πrh
length of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm
playground=31680×500=15840000cm 2
=1584m^2
Answered by
7
Answer:
Radius of the roller (r)=
84/2 cm=42cm
cm=42cmlength of the roller (h)=120cm
cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh
cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm
cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2
cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2
cm=42cmlength of the roller (h)=120cm∴ Area of the playground levelled in taking 1 complete revolution 2πrh=2×227×42×120=31680cm 2 ∴ Area of the playground
=31680×500=15840000cm ^2
15840000/ 100*100m^2
=1584m ^2
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