The diameter of a roller is 84cm and its length is 120cm. It takes 500 complete
revolutions to move once over to level a play ground. Find the area of the play ground.
explain step by step clearly
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4
Answer:
the roller takes 500 complete revolutions to roll once over that playground. Since a roller is in cylindrical shape. Lateral surface area = 2*Pie*r*h = 2*22/7*42cm*120cm = 31680cm2.
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Answered by
3
The diameter of a roller is 84cm and its length is 120cm. It takes 500 complete revolutions to move once over to level a play ground. Find the area of the play ground.
- Diameter of roller = 84cm so radius = 84/2 = 42 cm
- length(h) of roller is 120cm
- it take 500 complete revolution to move once over to level the play ground .
- Area = ?
We know,
- Curved surface area of cylinder = 2πrh
→
→
→
→
- CURVED SURFACE AREA 31680 cm^ = 1 REVOLUTION
- The roller takes 500 complete revolutions to move once over to level a play playground.
Area of playground = 31680 × 500
Area of playground = 15840000 cm
- Changing in
So
→ 15840000 ÷ 10000
→ 1584
- AREA OF PLAYGROUND =
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