Question

The diameter of a roller is 84cm and the length is 120cm.It takes 500
revolutions to move over to level a ground. Find the area of the ground in sq.m

Answer 1

Answer:

The diameter of a roller is 84 cm and its length is 120 cm and it takes 500 complete revolutions to move once over the level of a playground.  

The radius of the roller is 84/2=42cm

Given, Radius of the roller is 42cm and the height of the roller is 120cm.

Area of the playground in taking one revolution is equal the 2πrh

= 2*22/7*42*120

= 31680 cm squared

And it takes 500 revolutions so, the area of the playground is

= 31680*500

= 15840000 cm squared

= Now the area of the playground is in m squared so,

15840000 / 10000

= 1584m squared

The area of the playground is 1584m squared

Hope its helps u

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Answer 2

Answer:

$1584m^{2}$

Step-by-step explanation:

Radius of the roller (r)=  

2

84

​

cm=42cm

length of the roller (h)=120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh

=2×227×42×120=31680cm$^{2}$

 

∴ Area of the playground

=31680×500=$15840000m^{2}$  

 

100×100

15840000

​

$m^{2}$  

=$1584^{2}$

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