Math, asked by ARTHIMP6920, 1 year ago

The diameter of a roller roller 126 long is 84cm if it takes 500 complete revolution to level a playground determine the cost of levelling it @ rupees 30 per square metre

Answers

Answered by bristibidi
6
length of the roller (h) = 120cm= 1.2m
diameter of the roller = 84cm
radius of the roller(r) = 42 cm =4.2m
area covered by the roller in one revolution = curved surface area of the cylinder =2πrh
=2x22/7x
0.42x1.2
= 44x0.072
= 3.168m^2
area covered by the roller in 500 revolutions= 3.168x500=1584m^2
now,
cost of levelling 1m^2 = 30p
cost of levelling 1584m^2 =1584x30=47520p=rs47.52
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