Question

The diameter of a semicircular field is 14 meter then find it's perimeter
A 46
B 36
C 40
D 42

Answer 1

The perimeter of a semicircle is (πr + 2r).

------ ( where r = radius)

Given diameter : 14 m.

or radius : $\frac{14}{2}$m

= 7m

Hence, the perimeter will be :

$( \frac{22}{7} \times 7) + (2 \times 7 )\: m$

= (22 + 14) m

= 36 m

(B) 36 is the right answer.

Hope, it helped you.