Question

The diameter of a semicircular field is 14 meter,then its perimeter is

Answer 1

diameter=14
radius=14/2= 7m
perimeter of semicircle=πr= 22/7*7=22m

Answer 2

The perimeter of semicircle is 36 meter

Solution:

Given that,

Diameter of a semicircular field is 14 meter

d = 14 meter

The perimeter of semicircle is given by:

$Perimeter =\frac{1}{2} \times \pi d + d$

Substitute d = 14

$Perimeter = \frac{1}{2} \times \frac{22}{7} \times 14 + 14 \\\\Perimeter = 22 + 14\\\\Perimeter = 36$

Thus perimeter of semicircle is 36 meter

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