Physics, asked by lavanya8624, 7 months ago

The diameter of a sphere is 2.14 cm.
Calculate the volume of the sphere to the
correct number of significant figures.

Answers

Answered by sksyatharthrajawat
0

Explanation:

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Answered by aryan073
11

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  \bigstar \sf \large \underline \purple{given}

 \:  \:  \:  \: \:  \:  \bigstar  \huge \small { \sf \red{the \: diameter \: of \: a \: sphere \: is \: 2.14cm}}

 \:  \:  \:  \:  \:  \:  \mapsto \sf \pink{volume \: of \: sphere =  \frac{4}{3} \pi {r}^{3} }

 \:  \:  \:  \:  \:  \:  \mapsto \sf{d = 2r}

 \:  \:  \:  \:  \:  \:  \mapsto \sf{2r = 2.14}

 \:  \:  \:  \:  \:  \:  \mapsto \sf{r =  \cancel \red{ \frac{2.14}{2} }} = \green{ 1.07cm}

 \:  \:  \:  \:  \implies \boxed {\rm \: put \: the \: value \: in \: volume \: of \: sphere}

 \:  \:  \:  \:  \:  \:  \mapsto  \bf {v =  \frac{4}{3}  \times 3.14 \times {(1.07)}^{3} }

 \:  \:  \:  \:  \:  \:  \mapsto \bf{v = 1.33 \times 3.14 \times  {(1.07)}^{3} }

 \:  \:  \:  \:  \:  \mapsto \bf{v = 5.0006...... =  \approx \: 5.00 {cm}^{3} }

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