Math, asked by durgaraya, 21 days ago

The diameter of a sphere is decreased by 20%. By what percent does its curved surface area increase or decrease?​

Answers

Answered by vinay200421kumar
0

Answer:

it will decrease it is very simple bro

Answered by palsabita1957
43

Let the diameter of sphere be "d"

Curved surface area of sphere = 4πr²

 = π(2r)²

 = πd²

Given diameter of sphere decreases by 20%

New diameter =d − (\frac{d}{5}) = \bold{\frac{4d}{5}}

​New curved surface area =π(\frac{4d}{5})^{2} = \bold{\frac{16}{25}} πd²  

Change in surface area of sphere

=πd²  – (\frac{16}{25} )πd²  = (\bold{\frac{9}{25}} )πd²

 

Decrease in curved surface area

= \sf{\frac{\frac{9}{25} \pi d^{2}}{\pi d^{2}} } × 100 = 36%

∴ Surface area decreases by 36%

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