The diameter of a sphere is decreased by 25percent what percent its surface area decrease
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Step-by-step explanation:
Let me try to answer this in detail.
Let D be the diameter of the sphere, and the radius of the sphere r is D2.
The curved surface area of the sphere is A=4πr2=4πD2=πD2.
Since the diameter is decreased by 25, the new diameter is75100×d=3d4.
New surface area=4πr2=4π(3d2⋅4)2=916πd2
Decrease in surface area=πd2−916πd2=716πd2
So the % decrease in Surface Area=DecreaseinsurfaceareaSurfacearea×100%
=7πd216πd2×100=716×100=43.75%
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