Question

The diameter of a sphere is decreased by 50%. What is the ratio between initial and final curved surface areas?​

Answer 1

Using Curve surface are = 2πr²

d1 = d/2

d2 = d/4

After solving

Ratio = 1:2

Hope its helps you

Answer 2

■■ Points to Remember ■■

☆ Curved Surface Area of Sphere = ${4 \pi r^2}$

☆ Diameter = ${2 × radius = 2r}$

■■ Solution ■■

Let the initial radius be "x". Then, the initial diameter will be "2x".

Now,

Ratio =

${\mapsto \frac{4 \pi r^2}{4 \pi \frac{r}{2}}}$

${\mapsto 4:1 }$

$\mathcal{ Answer \implies 4:1}$

$\mathcal\color{maroon}{Bebrainly}$