The diameter of a spherical balloon increases from 14cm to 28 cm as air is being pumped into it find the ratio of surface area of the balloons
in two cases
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Answered by
107
Hiii !
We know Surface area of a sphere = 4πr²
let d1 be the diameter of the first balloon and d2 be the diameter of the new balloon.
∴ d1 = 14cm and d2 = 28 cm
now, r1 = 14/2= 7cm and r2 = 28/2 = 14 cm
surface area of first ballon = 4×(22÷7)×7×7
= 616 cm²
surface area of second balloon = 4×(22÷7)×14×14
= 2464 cm²
∴ the ratio of the two balloons = 616/2464 = 308/1232 = 154/616 = 77/308
= 1/4
⇒ ratio = 1:4
__________________________________________________________
HOPE IT HELPS :)
#BrainofBrainly
We know Surface area of a sphere = 4πr²
let d1 be the diameter of the first balloon and d2 be the diameter of the new balloon.
∴ d1 = 14cm and d2 = 28 cm
now, r1 = 14/2= 7cm and r2 = 28/2 = 14 cm
surface area of first ballon = 4×(22÷7)×7×7
= 616 cm²
surface area of second balloon = 4×(22÷7)×14×14
= 2464 cm²
∴ the ratio of the two balloons = 616/2464 = 308/1232 = 154/616 = 77/308
= 1/4
⇒ ratio = 1:4
__________________________________________________________
HOPE IT HELPS :)
#BrainofBrainly
ganesh59:
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Answered by
20
Answer:
the ratio of the two balloon
616/ 2464
do cancellation with 2 table
u get the answer 1/4 =1:4.
hope u guys it's help full tu u
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