Physics, asked by mamta44, 6 months ago

the diameter of a thin wire is measured with screw gauge. in successive measurements, the values of the diameter of the wire are 2.04mm, 2.06mm, 2.08mm, 2.07mm and 2.05mm. find (I). average diameter of the wire, (ii). absolute error, (iii). mean absolute error, (iv). relative error, and (v). percentage error​

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Answered by amreet28
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Question From class 11 Chapter PHYSICAL WORLD AND MEASUREMENT

The diameter of a wire as measured by a screw gauge was found to be 0.026 cm, 0.028 cm, 0.029 cm, 0.027cm, 0.024cm and 0.027 cm. Calculate <br> (i) mean value of diameter <br> (ii) mean absoulte error <br> (iii) relative error (iv) percentage error. Also express the result in terms of absolute error and percentage error.

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Text Solution

Answer :

(i) 0.027cm 9ii) 0.001 cm(iii) 0.037 (iv) 3.7 % (0.027 +- 0.001) cm <br> 0.027 cm +- 3.7 %

Solution :

(i) Mean value of diameter, <br>

<br>

<br> Now,

<br>

<br>

<br>

<br>

<br>

<br> (ii) Mean absolute arror

<br>

<br>

<br>

<br>(iii) Relative error

<br> (iv) Percentage error

<br> (v) Diameter of wire

<br>

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