Question

The diameter of a thin wire is measured with screw gauge. The values of diameter of wire are 2.04mm, 2.06mm, 2.08mm, 2.07mm & 2.05mm. Find 1) Average diameter of wire 2) Absolute error 3) Mean absolute error 4) Relative error 5) Percentage error

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Answer 1

Answer:

Average diameter = D = (2.04 + 2.06 +2.06 + 2.08 + 2.07 + 2.05)/6

or, D = 2.06

Absolute errors in measurements

D1 = 2.06 – 2.04 = 0.02 mm

D2 = 2.06 – 2.06 = 0

D3 = 2.06 – 2.06 = 0

D4 = 2.06 – 2.08 = - 0.02 mm

D5 = 2.06 – 2.07 = - 0.01 mm

D6 = 2.06 – 2.05 = 0.01 mm

Mean absolute error,

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Answer 2

The diameter of a thin wire is measured with screw gauge. The values of diameter of wire are 2.04mm, 2.06mm, 2.08mm, 2.07mm & 2.05mm. Find 1) Average diameter of wire 2) Absolute error 3) Mean absolute error 4) Relative error 5) Percentage error

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