Question

The diameter of a wire as measured by a screw gauge was found to be 1.002 cm 1.000 cm and 1.006 cm the absolute error in the second reading is

Answer 1

First calculate the true vale, i.e., mean of 1 cm, 1.002 cm and 1.006 cm.

True Value= 1.0026667 or 1.003(in round figures)

Absolute Error= |(measured value) - (true value)| = |1.000-1.003| = |-0.003|=0.003

Answer 2

Answer:

The absolute error in the second reading = 0.002 cm

Explanation:

Given,

The diameter of a wire as measured by a screw gauge are 1.002 cm 1.000 cm and 1.006 cm.

For the three readings:

mean    $=\frac{1.002+1.000+1.006}{3}\ cm = 1.002 \ cm$

So, absolute error in the second reading ($E_{a}$) = $|Measured Value - Mean|$

                                                                            $= |1.000 - 1.002| \ cm$

                                                                            = 0.002 cm

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