Question

The diameter of a wire as measured by a screw guage was found to be 0.026cm, 0.028cm, 0.029cm,0.027cm, 0.024cm, 0.027cm. Calculate. 1 - Mean Value of Diameter.. 2 - Mean Absolutely Error.. 3 - Relative and Percentage error.. 4 - Express the diameter with Relative and Percentage error​

Answer 1

Answer:

1. 0.0268 cm

2. 0.0012

3. 0.045, 4.5%

4. 0.0268 cm +/- 0.045

0.0268 cm +/- 4.5%

Explanation:

a(mean) = (0.026+0.028+0.029+0.027+0.024+0.027)/6

=0.0268 cm

da1=0.0008

da2=0.0012

da3=0.0022

da4=0.0002

da5=0.0028

da6=0.0002

da(mean) = 0.0012

R.E.= 0.0012/0.0268 =0.045

%error= 4.5