Math, asked by bhupinderthakur27, 6 months ago

The diameter of an electric cable. Say X, is assumed to be a continuous random variable

with p.d.f.: f(x) = 6x(1 – x), 0  x  1.

i) Check that f(x) is p.d.f.

ii) Determine a number b such that P(X < b) = P(X > b).​

Answers

Answered by aayush2004tanwar18
0

Answer:

Given : The diameter of an electric cable, Say X, is assumed to be continuous random variable with p.d.f f (x)= 6x(1-x), 0 ≤ x ≤ 1

To find : Show that f(x) is a p.d.f. (probability density function )

Solution:

f(x) = 6x(1 - x) 0 ≤ x ≤ 1

Function f(x) is a probability density function in range a to b

if \int\limits^b_a {f(x)} \, dx = 1

a

b

f(x)dx=1

f(x) = 6x(1 - x)

f(x) = 6x - 6x²

\int\limits^1_0 {(6x - 6x^2)} \, dx

0

1

(6x−6x

2

)dx

= [ \frac{6x^2}{2} - \frac{6x^3}{3} ] ^1_0[

2

6x

2

3

6x

3

]

0

1

= [ 3x^2 - 2x^3 ] ^1_0[3x

2

−2x

3

]

0

1

= 3(1)² - 2(1)³ - ( 0 - 0)

= 3 - 2 - 0

= 1

\int\limits^1_0 {(6x - 6x^2)} \, dx

0

1

(6x−6x

2

)dx = 1

Hence f(x) = 6x(1 - x) 0 ≤ x ≤ 1 is pdf ( probability density function )

Answered by lalitk7602
0

Answer:

The diameter of an electric cable. Say X, is assumed to be a continuous random variable

with p.d.f.: f(x) = 6x(1 – x), 0  x  1.

i) Check that f(x) is p.d.f.

ii) Determine a number b such that P(X < b) = P(X > b).

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