Question

the diameter of aperture of an astronomical telescope is 1.22m what should be minimum separation between 2 objects at a distance 10km from the telescope to observe them distinctively(take wavelength of light to be 5000A)​

Answer 1

Correct Answer: C

Solution :

          θ=xd=1.22λa       ⇒x=1.22×da =1.22×5000×10−10×10310×10−2= 6.1 mm i.e. order will be 5 mm.