The diameter of circular park is 28 m. A road 1.75m wide runs around it.find the cost of gravelling the road at 5 per m2
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Step-by-step explanation:
Solution now radius =28/2.
.Width of road is 1.75m.
now radius of outer circle is =14+1.75=15.75.
.
.
Area of road=( Area of outer circle - Area of inner circle).
=π×(15 .75)*2-π×(14)*2.
=π×{(15.75)*2-(14)*2}.
=π×{(15.75-14)(15.75+14)}.
π×29.75×1.75.
22/7×29.75×1.75.
=7.4375×22.
.-- >163.625m/sq.
so the cost of road =163.625×5.
.Answer=RS=818.125
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Answer:gg
Step-by-step explanation:
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